CAUTION: While it is possible to initialize structure variables by using a "list", this method does not apply when the structure uses apvector, apmatrix, or apstring. |
 |
|
struct TREE_TYPE
{
int month;
int day;
int year;
};
int main(void)
{
TREE_TYPE treePlanted = { 04, 02, 1980 };
//filling by list
TREE_TYPE treeHarvested = { 06, 11, 2001 };
. . .
As with all variables, structures
can be filled by assignment, with user input, or from a
file. Notice how the dot (.) operator is used to reference each member of
the structure in the examples below:
|
By Assignment: |
By User Input: |
. . .
struct STUDENT_TYPE
{
apstring name, street, city, state, zip;
int age;
double IDnum;
double grade;
} ;
int main(void)
{
// Declare a struct
STUDENT_TYPE student1;
// initialize the members of the
struct
student1.name = '"Garfield";
student1.street = "123 Mouse Lane";
student1.city = "Catsville";
student1.state = "PAW";
student1.zip = "12345";
student1.age = 3;
student1.IDnum = 101010101;
student1.grade = 98.5;
. . . |
struct STUDENT_TYPE
{
apstring name, street, city, state, zip;
int age;
double IDnum;
double grade;
} ;
int main(void)
{
// Declare an array of structs
apvector<STUDENT_TYPE> roster(10);
// fill the array of structs
for (int i = 0; i<10; i++)
{
cout<<"Please enter info "
<<"for student "<<i+1<<endl;
cout<<"Enter the name: ";
getline(cin, roster[ i ].name );
…
cout<"Enter the age: ";
cin>> roster[ i ].age;
. . . |
It is possible to use a structure to define another
structure, thus creating "nested" structures :
struct ADDRESS_TYPE
{
apstring street, city, zipcode;
};
struct STUDENT_TYPE
{
apstring name;
ADDRESS_TYPE address;
int age;
double IDnum;
double grade;
};
|
